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8.CHEMICAL EQUILIBRIUM eLearn.Punjab
(b) Determination of Solubility from Ksp
For this purpose we need the formula of the compound and Ksp value. Then the unknown
molar solubility S is calculated and the concentration of the ions are determined. Table (8 .11 ) shows
the relationship between the Ksp values and the solubility of some sparingly soluble compounds.
Table (8.11) Relationship between Ksp and the
solubility of some compounds.
Formula No. of Ksp Solubility
ions Cation gdm-3
3.61x10-8
Anion 1.69x10-8 1.9x10-4
1.96x10-10 1.3x10-4
MgCO3 2 1/1 6.5x10-6 1.4x10-5
PbSO4 2 1/1 1.35x10-5 1.175x10-2
BaCrO4 2 1/1 3.2x10-11 7.2x10-3
Ca(OH)2 3 1/ 2 2.6x10-12 2.0x10-4
BaF2 3 1/ 2 8.7x10-5
CaF2 3 1/ 2
Ag2CrO4 2 /1
Example 7 :
Ca(OH)2 is a sparingly soluble compound. Its solubility product is 6.5x10-6 Calculate the
solubility of Ca(OH)2.
Solution:
Let the solubility is represented by S in terms of moles dm-3.
The balanced equation is
Ca(OH)2  Ca2+ (aq) + 2OH-(aq)
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