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8.CHEMICAL EQUILIBRIUM                                              eLearn.Punjab

					

(b) 	 Determination of Solubility from Ksp

	 For this purpose we need the formula of the compound and Ksp value. Then the unknown
molar solubility S is calculated and the concentration of the ions are determined. Table (8 .11 ) shows

the relationship between the Ksp values and the solubility of some sparingly soluble compounds.

Table (8.11) Relationship between Ksp and the
         solubility of some compounds.

Formula No. of                                  Ksp     Solubility
              ions Cation                                  gdm-3
                                            3.61x10-8
                             Anion          1.69x10-8   1.9x10-4
                                            1.96x10-10  1.3x10-4
MgCO3                   2  1/1              6.5x10-6    1.4x10-5
PbSO4                   2  1/1              1.35x10-5   1.175x10-2
BaCrO4                  2  1/1              3.2x10-11   7.2x10-3
Ca(OH)2                 3  1/ 2             2.6x10-12   2.0x10-4
BaF2                    3  1/ 2                         8.7x10-5
CaF2                    3  1/ 2
Ag2CrO4                    2 /1

Example 7 :

	Ca(OH)2 is a sparingly soluble compound. Its solubility product is 6.5x10-6 Calculate the
solubility of Ca(OH)2.

Solution:

	 Let the solubility is represented by S in terms of moles dm-3.
	 The balanced equation is

			 Ca(OH)2  Ca2+ (aq) + 2OH-(aq)

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