Page 14 - 10-Math-1 QUADRATIC EQUATIONS
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or 3x + 7 = 4x2 + 12x + 9
Simplifying the above equation, we have 4x2 + 9x + 2 = 0
Applying quadratic formula,
Note : Extraneous root
is introduced either by
squaring the given
equation or clearing it
Checking: 1 of fractions.
Putting x = - 4 in the equation (i), we have
which is true.
Putting x = -2 in the equation (i), we get
which is not true.
On checking, we find that x = -2 does not satisfy the equation (i),
so it is an extraneous root. Thus the solution set is
1.5 (ii) Equations of the type x + a + x + b = x + c
Example 2: Solve the equation
Solution: (i)
Squaring both sides of the equation (i), we have
Version 1.1 Squaring both sides of the equation (ii), we get
4(x2 + 9x + 18) = x2 - 4x + 4
or 3x2 + 40x + 68 = 0
Applying quadratic formula, we get
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