Page 15 - 10-Math-1 QUADRATIC EQUATIONS
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1.5(iii) Equations of the type:                               Version 1.1

Example 3:  Solve the equation x2 - 3x + 36 - x2 - 3x + 9 =3
Solution:
Then
Squaring both sides, we get

Again squaring both sides, we get
y2 + 45y + 324 = y2 + 36y + 324
9y = 0    ⇒     y = 0
As	 x2 - 3x = y , so  x2 - 3x = 0
⇒    x(x - 3) = 0

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