Page 15 - 10-Math-1 QUADRATIC EQUATIONS
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1.5(iii) Equations of the type: Version 1.1
Example 3: Solve the equation x2 - 3x + 36 - x2 - 3x + 9 =3
Solution:
Then
Squaring both sides, we get
Again squaring both sides, we get
y2 + 45y + 324 = y2 + 36y + 324
9y = 0 ⇒ y = 0
As x2 - 3x = y , so x2 - 3x = 0
⇒ x(x - 3) = 0
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