Page 4 - 10-Math-10 TANGENT TO A CIRCLE
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Theorem 2
10.1 (ii) The tangent to a circle and the radial segment joining
the point of contact and the centre are perpendicular to each
other.
Given: In a circle↔with centre O has
radius OC, Also AB is the tangent
to the circle at point C.
↔
To prove: AB and radial segment OC are perpendicular to each
other.
C↔onstruction: Take any point P other than C on the tangent line
AB . Join O with P so that OP meets the circle at D.
Proof:
Statements Reasons
↔ Given
AB is the tangent to the circle at point Construction
C. Whereas OP cuts the circle at D.
∴ mOC = mOP (i) Radii of the same circle
But mOD < mOP Point P is outside the
(ii) circle.
∴ mOC < mOP Using (i) and (ii)
So radius OC is shortest of all lines that
c↔an be drawn from O to the tangent line
AB
↔
Also OC AB
Hence, radial segment OC is ↔
perpendicular to the tangent AB .
Corollary: There can only be one perpendicular drawn to the radial
segment OC at the point C of the circle. It follows that one and only
one tangent can be drawn to the circle at the given point C on its
circumference.
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