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21.. DQifufaerdernattiiactEioqnuations                                                                                          eeLLeeaarrnn..PPuunnjjaabb
                                                                                                                                  version: 1.1
	  When         y  ∈     -  π      ,0     ,cosec  y   and     cot    y   are    negative
                           2          

	 As cosec y = x, so x is negative in this case
	 and cot y = - cosec2 y -1 = - x2 -1 when x < -1

                                                 -1
                                            x - x2 -1
   ( )Thu=s ddx Co sec-1 x                                             ( x < -1)

	                                                       -1

   =                                        (-x) x2 -1                        ( x < -1)

		 	ddx co	sec-1 x	 = - | x |           1                          for x ∈[-1,1]'
                                            x2 -1

Proof of (5). is left as an exercise
Proof of (6). is similar to that of (4)

Example 1:            Find dy if =y                             x  Sin     -1  x     +     a2 + x2
                            dx                                                    a  
             	

Solution: 	 Given that=y                       x  Sin   -1     x     +   a2 + x2
                                                              a  

	 Differentiating w.r.t. x , we have

( )		=dy              d                     x                                 d       x         x        d
                dx    dx                    a                                 dx                   a       dx
                                x  Sin-1      +        a=2 + x2                         Sin-1         +      a2 + x2  1/ 2
                             

         1 . Sin-1 x + x.                         1                d      x        1                    d1 -1
                  a                                                dx    a       2
        ( ) ( )=                                           2   .                 +         .  a2  +  x2  2      a2 + x2
                                                           
		                                          1  -       x                                                    dx
		                                                    a

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