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    <pre style="white-space:pre-line"><code>16.. FQaucatodrriazatitcioEnq, Suiamtiuolntasneous Equations                              eeLleeaarrnn..pPuunnjjaabb

                            EXERCISE 6.9

1. Find the solution set by using the method of equating the coefficients.

(i) 2x + 5y = -1                                              (ii) x + y = 2

         x - 2y = 4                                           x-y=0

(iii) 2x + 3y = 3                                             (iv) x - 4y = 4

         x + 5y = 5                                           4x - y = 16

(v) 2x - 3y = 6                                               (vi) 3x - 4y = 7

         3x + 5y = 0                                          5x + y = 27

2. Find the solution set by using the method of elimination by substitution.

(i) 2x + 2y = 5                                               (ii) 5x + 2y = 15

         x - 2y = 3                                           -2x + y = 4

(iii) 6x + y = 2                                              (iv) 2x + 7y = 10

         x - 4y=15                                            3x + y = 3

(v) 2x - 4y = -10                                             (vi) x + 8y = 15

         y + 5x = -5                                          3x - y = 0

3. Find the solution set by using the method of cross multiplication.

(i) 2x - 7y = 11                                              (ii) 11x + 12y = 15

         5x - 10y = 10                                        12x + 11y = -23

  (iii)  2x - 9y + 10 = 0                                     (iv) 5x + y - 56 = 0
         3x - 5y - 10 = 0                                               x + 18y - 29 = 0
  (v)    9x - 11y - 15 = 0
         7x - 13y - 25 = 0                                    (vi) 2y - 10x - 86 = 0
	                                                                       2x + 5y - 11 = 0

6.5.2	   Solving Real Life Problems Involving Two Simultaneous Linear
	        Equations in two Variables

Example 1: A number is half of another number. The sum of 3 times of 1st number and 4
times of 2nd number is 22. Find the numbers.

Solution: Suppose that the numbers are x and y. Then according to given condition.

                                                                                                                     version: 1.1

                                                              20</code></pre>
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