Page 12 - 12-phy-15 ELECTROMAGNETIC INDUCTION
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15. Electromagnetic Induction                                                                             eLearn.Punjab


        Example 15.2: A loop of wire is placed In a uniform magnetic field that is perpendicular to the

        plane of the loop. The strength of the magnetic field is 0.6 T. The area of the loop begins to shrink
        at a constant rate of DA/Dt = 0.8 m s . What is the magnitude of emf induced in the loop while it is
                                                     2 -1
        shrinking?



        Solution:


                                                                           DA
                                   Rate of change of area =                      =  0.8m s       1
                                                                                             2 −
                                                                            Dt

                                                                                                         1
                                   Magnetic flux density = B                 =   0.6T =     0.6NA m          −  1
                                                                                                       −
                                                                     =
                                   Number of turns =             N 1

                                   Induced emf = e=              ?


                                                                       Df           DA                     DA
                                                                                                 o
                               Rate of change of flux =                      = B          cos0 = B
                                                                        D           Dt  t                  D  t

                              Applying Faraday's Law, magnitude of induced emf


                                                            Df             DA
                                                  e=    N         =  NB
                                                            D               Dt  t

                                                                              1
                                                                        1
                                                     = 1x0.6NA m x0.8m s                      1
                                                                                         2 −
                                                                            −
                                                                       −
                                                                    1
                                                                  −
                                                 e=    0.48JC =          0.48V

        15.4 LENZ’S LAW AND DIRECTION OF INDUCED EMF









        In the previous section, a mathematical expression of the Faraday’s law of electromagnetic induction

        was derived as

                                                                           Df
                                                               e= −     N
                                                                            Dt






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